k^2-2k-124=0

Solution for k^2-2k-124=0 equation:

k^2-2k-124=0

a = 1; b = -2; c = -124;
Δ = b2-4ac
Δ = -22-4·1·(-124)
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10\sqrt{5}}{2*1}=\frac{2-10\sqrt{5}}{2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10\sqrt{5}}{2*1}=\frac{2+10\sqrt{5}}{2}
$